You are correct that oxidation is the loss of electrons and reduction is the gaining of electrons. 0 = H 2 O 2 = (2 * +1) + (2 * -1) = 0. To neutral that -2 charge, +2 charge should be there and it is given by Pb 2+ ion. Oxidation number of O=-2. Oxidation number of S=+6. Within polyatomic ions, you can frequently have oxidation states that are not "normal". Pb + PbO2 + 2H2SO4 → 2PbSO4 + 2H2O Pb PbO2 PbSO4 H2O H2SO4. How to calculate oxidation number of Pb in PbSO4?And Explain? This clearly shows that PbO2 is formed as a new phase which nucleates in the pores. Expert Answer: Let the oxidation number of Pb=x. PbSO 4 salt does not have an overall charge. I don't think that you have written the formula of the calcium compound correctly. The sum of the oxidation numbers in a monatomic ion is equal to the overall charge of that ion. Check what the oxidation states of the elements are. The change in the oxidation number of the underlined nitrogen atom in the following chemical reactions are : a. Nitrous acid (H N O 2 ) reduces M n O 4 ⊖ in acid solution. PbSO4 H2O H2SO4 PbO2. Related Tutorials to PbS 2 + H 2 O 2. Since the ion has a -2 charge, the oxidation state of sulfur must be +6. The oxidation of PbSO4 to PbO2 was studied by sweeps to positive potentials where the PbSO4 membrane is destroyed. The SO4 has the same oxidation numbers as in PbSO4 above.In working out oxidation numbers we assume that certain elements have fixed numbers O is -2, Cl is -1, H is +1 and alkali metals like sodium and potassium are +1. What is the oxidation number of phosphorous in the H3PO2 molecule? PbO2. Chlorine, bromine, and iodine usually have an oxidation number of –1, unless they’re in combination with oxygen or fluorine. 172 < 20 :3_ 10 Electrochemical oxidation of the PbSO4 layer. Pb. H will have an oxidation state of +1. Asked by | 25th Mar, 2009, 06:56: PM. H is +1 when not bound to a metal, O and S are -2 when bound to elements of lower electronegativity only. Therefore oxidation number of Pb is +2. Which substance is the reducing agent in the following reaction? Electron micrograph of the initial stage of PbO2 formation. The oxidation number of fluorine is always –1. But Sulfate ion has -2 charge. With 2 +1 ON in H2O2, the O2 entity has to be -2, meaning O is -1. The next, PbS is also electrically neutral. So, SO42- can be dealt with on its own. Now, since O is always -2, the S must be +6 to make the whole compound zero. But, in this particular case it has an oxidation state of -1. Fig. b. Nitrous acid (H N O 2 ) oxidises I ⊖ to I 2 in acid solution. H2O2 + PbS --> PbSO4 + H2O. A compound doesn't have an oxidation number, but an element in a compound does. For a simple ion, like Pb in PbSO4, it is the same as the ionic charge, ie +2. 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